Q73
ArithmeticAlgebra, Equations & Operations
The remainder, when $(x^3 + 3x^2 + 3x + 1)$ is divided by $(x - 1)$, is
- a.1
- b.0
- c.2
- d.8
Answer: (D) 8
By the remainder theorem the remainder is the value at $x = 1$: 1 + 3 + 3 + 1 = 8. Equivalently the polynomial is $(x + 1)^3$ and $2^3 = 8$. 0 would be the remainder on dividing by $(x + 1)$.