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WBCS Main Examination 2023 — Paper VI: Arithmetic and Test of Reasoning · Question 73 of 200

Q73
ArithmeticAlgebra, Equations & Operations
The remainder, when $(x^3 + 3x^2 + 3x + 1)$ is divided by $(x - 1)$, is
  1. a.1
  2. b.0
  3. c.2
  4. d.8

Answer: (D) 8

By the remainder theorem the remainder is the value at $x = 1$: 1 + 3 + 3 + 1 = 8. Equivalently the polynomial is $(x + 1)^3$ and $2^3 = 8$. 0 would be the remainder on dividing by $(x + 1)$.

The remainder, when (x^3 + 3x^2 + 3x + 1) is divided by (x - 1), is — WBCS Main Examination 2023 Q73 | Prostuti360°