Q79
ArithmeticGeometry & Mensuration
If the distance of the point (–12, y) from origin is 20 unit, then value of y is
- a.± 15
- b.± 16
- c.± 14
- d.None of the above
Answer: (B) ± 16
By the distance formula $(-12)^2 + y^2 = 20^2$, so $y^2 = 400 - 144 = 256$ and $y = \pm 16$. This is the 12-16-20 right triangle, so ± 15 and ± 14 do not fit.