Q189
ArithmeticAverages & Ages
The age of father is twice that of elder son. Ten years hence, the age of the father will be three times that of the younger son. If the difference of ages of the two sons is 15 years, find the age of the father.
- a.50 years
- b.55 years
- c.60 years
- d.70 years
Answer: (A) 50 years
Let elder son's age = x years. Father's age = 2x. Younger son's age = x - 15. Ten years hence: father = 2x+10, younger son = x-15+10 = x-5. Condition: 2x+10 = 3(x-5) → 2x+10 = 3x-15 → x = 25. Father's age = 2×25 = 50 years.