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WBCS Preliminary Examination 2022 — General Studies · Question 196 of 200

Q196
ReasoningCoding-Decoding
In a certain code KOLKATA is coded as 1115121101200l. How will BENGAL be coded?
  1. a.020514070112
  2. b.020514210111
  3. c.020521250110
  4. d.020514200112

Answer: (A) 020514070112

KOLKATA: K=11, O=15, L=12, K=11, A=01, T=20, A=01 → 1115121101200l. Each letter is replaced by its 2-digit position in the alphabet (A=01, B=02…Z=26). BENGAL: B=02, E=05, N=14, G=07, A=01, L=12 → 020514070112.

Q195 Whole paperQ197