Q21
ArithmeticGeometry & Mensuration
The diagonal of a square is $4\sqrt{2}$ cm. The diagonal of another square whose area is double that of the first square, is
- a.8 cm
- b.$8\sqrt{2}$ cm
- c.16 cm
- d.$4\sqrt{2}$ cm
Answer: (A) 8 cm
The first square's area is $\frac{d^2}{2} = \frac{32}{2} = 16$ cm², so the second square's area is 32 cm². Its diagonal satisfies $\frac{d^2}{2} = 32$, so $d = 8$ cm. $8\sqrt{2}$ cm would correspond to doubling the diagonal (four times the area).